Two Weapons / Multiple Attack

[Brandon Stubbs]

On Tue, 2 Apr 2002 18:18:32 +0200, Matijs van Zuijlen
<Matijs.van.Zuijlen at XS4ALL.NL> wrote:

>I'm confused here. Is the 12 coming from the number of seconds per
>turn? That would seem to be the case, given your crossbow formula.
>Still, I don't see why you would divide by the number of seconds per
>turn to get the number of shots per turn (Since I understand from your
>later post that you mean turn when you say round). I just don't see the
>rationale behind the formula.

I play my tactical turns different than what I suppose most people
understand it. I base each attack not on one phase(3 seconds) but on a Turn
(12 seconds). This is only logical in that there is time for small rests in
between attacks otherwise all would collaspe after only 2 or 3 minutes of
fighting. For those of you who have fought you know what I mean. Even in
the best of shape it's exausting to fight. There has to be lulls.
Phase 1: Magic is begun(3 sec's of words to gather mana), all combatants
began a little stragegy for next attack and gather strength.
Phase 2: Archer aims and fires. All combatants finish stratgy. Dodging
applies as movement.
Phase 3: Magic effect. Dodging magic applies. Combatants move into fighting
positions or flee.
Phase 4: Melee, dodge, fleeing or other movement depending on strategy.

That's the logic I apply to tactical turns. I try to make it as real as
possible.

>Another thing: How do you arrive at 1 attack every 3 turns for the worst
>case. Just using the formula gives (-27-1-1)/12 = -2. That's not 1/3. So
>I'm missing something here.
>
>Please enlighten me :).

I round up. Excel's roundup formula counts -2.4166 as 3, as do I. I suppose
if I was nice I'd round the other way, but I rather enjoy seeing a fumbling
greeny terrified. :-) JK

Thanks for your reply. It's kind of fun hearing everyones ideas.